-3x^2-26x+105=0

Solution for -3x^2-26x+105=0 equation:

-3x^2-26x+105=0

a = -3; b = -26; c = +105;
Δ = b2-4ac
Δ = -262-4·(-3)·105
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-44}{2*-3}=\frac{-18}{-6}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+44}{2*-3}=\frac{70}{-6}
=-11+2/3
$